Abstract
An isomeric 0+ state in 12Be was found at Ex = 2.24 MeV. The isomer was identified by measuring coincident two γ-rays from in-flight 12Be nuclei, 12mBe → 12Be* (21+) → 12Beg.s., produced by the projectile fragmentation of 18O at 100 A MeV on a beryllium target. Its spin was determined to be 0+ by the angular correlation of the two γ-rays. The low excitation energy of the 0+ state is a strong evidence of the break of the N = 8 shell closure in the 12Be nucleus.
| Original language | English |
|---|---|
| Pages (from-to) | 31-36 |
| Number of pages | 6 |
| Journal | Physics Letters, Section B: Nuclear, Elementary Particle and High-Energy Physics |
| Volume | 560 |
| Issue number | 1-2 |
| DOIs | |
| State | Published - 8 May 2003 |
| Externally published | Yes |
Keywords
- Isomeric state
- Radioactive beam experiment
- γ-γ correlation